Virat Kohli’s outstanding effort helped India defeat Australia by four wickets in an exciting semifinal at Dubai International Stadium on March 4, 2025, guaranteeing their place in the Champions Trophy final. India defeated Australia’s total of 264 all out, finishing at 267-6, thanks to Kohli’s 84 runs off 98 balls, his 74th ODI half-century.
On a slow pitch, India’s bowling assault, spearheaded by pacer Mohammed Shami, who had figures of 3-48 in 10 overs, successfully contained Australia. With 73 runs off 96 balls, Steve Smith led Australia in scoring, while Indian spinners Varun Chakravarthy and Ravindra Jadeja each took two wickets.
During India’s innings, Shreyas Iyer partnered with Kohli to add 91 runs for the third wicket, stabilizing the chase. Lokesh Rahul’s unbeaten 42 off 34 balls ensured India achieved the highest successful chase against Australia in an ICC event.
This victory means India will face the winner of the South Africa vs. New Zealand semifinal, scheduled for March 5 in Lahore, Pakistan. The final will take place in Dubai, as India’s progression dictates the venue; had they been eliminated, Lahore would have hosted the final.
Kohli emphasized the importance of handling pressure, stating, “This game is all about pressure—if you go deep, the opposition usually gives in.”
The upcoming final promises an exciting conclusion to the tournament, with India aiming to secure their second Champions Trophy title since 2013.
